from parso.parser import ParserSyntaxError
from parso.grammar import Grammar,load_grammar
from parso.utils import split_lines,python_bytes_to_unicode
__version__='0.8.4'
def parse(code=None,**A):'\n    A utility function to avoid loading grammars.\n    Params are documented in :py:meth:`parso.Grammar.parse`.\n\n    :param str version: The version used by :py:func:`parso.load_grammar`.\n    ';B=A.pop('version',None);C=load_grammar(version=B);return C.parse(code,**A)